2v^2-2V+40=v^2+16

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Solution for 2v^2-2V+40=v^2+16 equation: 


Simplifying
2v2 + -2V + 40 = v2 + 16

Reorder the terms:
40 + -2V + 2v2 = v2 + 16

Reorder the terms:
40 + -2V + 2v2 = 16 + v2

Solving
40 + -2V + 2v2 = 16 + v2

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -2V + -40 + 2v2 = 16 + -40 + v2

Reorder the terms:
40 + -40 + -2V + 2v2 = 16 + -40 + v2

Combine like terms: 40 + -40 = 0
0 + -2V + 2v2 = 16 + -40 + v2
-2V + 2v2 = 16 + -40 + v2

Combine like terms: 16 + -40 = -24
-2V + 2v2 = -24 + v2

Add '-2v2' to each side of the equation.
-2V + 2v2 + -2v2 = -24 + v2 + -2v2

Combine like terms: 2v2 + -2v2 = 0
-2V + 0 = -24 + v2 + -2v2
-2V = -24 + v2 + -2v2

Combine like terms: v2 + -2v2 = -1v2
-2V = -24 + -1v2

Divide each side by '-2'.
V = 12 + 0.5v2

Simplifying
V = 12 + 0.5v2

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